Challenging Geometry Puzzle: Problem 1570. Share your solution by posting it in the comment box provided.

Audience: Mathematics Education - K-12 Schools, Honors Geometry, and College Level.

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ReplyDeleteConnect AF and AC

We have AC/AB=AF/AE= sqrt(2)

Angle (EAB)= 90- ∡(BAG)

∡(FAC)=45+45-∡(BAG)= ∡(EAB)

Triangle FAC similar to EAB ( case SAS) with factor of similarity= sqrt(2)

So EB= FC/sqrt(2)= 3.sqrt(2)