Challenging Geometry Puzzle: Problem 1568. Share your solution by posting it in the comment box provided.

Audience: Mathematics Education - K-12 Schools, Honors Geometry, and College Level.

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ReplyDeleteConnect DC and note that DC perpendicular FG

We have angle(ADC)= 90+ angle (B)/2

And angle (JDC)= 180-(90+^B/2)= 90- ^(B)/2

So angle (DJH)= 90-angle(JDC)= ^(B)/2= angle (DBH)

So B, D, H, J are concyclic