Geometry Problem 1541. Post your solution in the comment box below.

Level: Mathematics Education, K-12 School, Honors Geometry, College.

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Very nice solution Pradyumna

ReplyDeleteThanks Sumith for your kind words.

ReplyDelete<ACD=<ABD=<ACF, AC is bisector of <DCF, BC_|_AC, so BC bisector of <FCG, thus 6/x=16(22+x), hence 10x=132, x=13.2

ReplyDelete