Geometry Problem 1519. Post your solution in the comment box below.
Level: Mathematics Education, K-12 School, Honors Geometry, College.
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x = 9 (simple Pr)
ReplyDeleteDraw FP// CD ( P is on AD)
ReplyDeleteSince F is the midpoint of AE so FP= .5*CD= 6
GH= 1/(FP+CD)= 9
Extend HG to meet BC at K. Draw FL // AB, L on BC
ReplyDeleteApplying mid point theorem to Tr.s ABE & CFL,
GK = FL/2 = (AB/2)/2 = AB / 4 = CD/4 = 12 / 4 = 3
Now CDHK is a parallelogram
So GH = HK - GK = 12 - 3 = 9
Sumith Peiris
Moratuwa
Sri Lanka