Geometry Problem 1511. Post your solution in the comment box below.

Level: Mathematics Education, K-12 School, Honors Geometry, College.

Details: Click on the figure below.

More Details

To post a solution to this problem click Comment underneath the post, or click into the line that says, “Enter Comment.” Type what you want to say and press Publish to post your solution.

To post a solution to this problem click Comment underneath the post, or click into the line that says, “Enter Comment.” Type what you want to say and press Publish to post your solution.

Let AB = BC = a

ReplyDeleteS(ABD) = S(ABC) + S(BCD)

So 8.a/2 = AH.a/2 + 5a/2

Hence AH = 3

Sumith Peiris

Moratuwa

Sri Lanka

x=3 (apply thales Theorem)

ReplyDeleteOn the sketch it will be explained

https://photos.app.goo.gl/SEth1bMRH4V6skpW8

DeleteSecond solution: https://photos.app.goo.gl/1K7fVwM8iboF94pa6

ReplyDelete