Geometry Problem 1511. Post your solution in the comment box below.
Level: Mathematics Education, K-12 School, Honors Geometry, College.
Details: Click on the figure below.
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Let AB = BC = a
ReplyDeleteS(ABD) = S(ABC) + S(BCD)
So 8.a/2 = AH.a/2 + 5a/2
Hence AH = 3
Sumith Peiris
Moratuwa
Sri Lanka
x=3 (apply thales Theorem)
ReplyDeleteOn the sketch it will be explained
https://photos.app.goo.gl/SEth1bMRH4V6skpW8
DeleteSecond solution: https://photos.app.goo.gl/1K7fVwM8iboF94pa6
ReplyDelete