Saturday, July 28, 2018

Geometry Problem 1369: Equilic Quadrilateral, 120 Degrees, Congruence, Midpoint, 60-120 degrees Rhombus, Polyiamond, Diamond

Geometry Problem. Post your solution in the comment box below.
Level: Mathematics Education, High School, Honors Geometry, College.

Details: Click on the figure below.

Geometry Problem 1369: Equilic Quadrilateral, 120 Degrees, Congruence, Midpoint, 60-120 degrees Rhombus.

Posted by Antonio Gutierrez at 10:44 AM
Labels: , , , ,

2 comments:

  1. c.t.e.oJuly 30, 2018 at 12:13 PM

    EF // GH, EF = FG => Rhombus

    ReplyDelete
  2. Sumith PeirisApril 21, 2020 at 10:38 AM

    EF//BC//GH and FG//CD//EH so EFGH is a parallelogram and since EF = AB/2 = CD/2 = FG EFGH is a rhombus

    Further < EHG = 180 - (120-@) - @ = 60 and so EFGH is a 60-120 Rhombus

    Sumith Peiris
    Moratuwa
    Sri Lanka

    ReplyDelete

Subscribe to: Post Comments (Atom)