tag:blogger.com,1999:blog-6933544261975483399.post4923058766851480219..comments2024-03-26T19:10:02.918-07:00Comments on Go Geometry (Problem Solutions): Geometry Problem 1369: Equilic Quadrilateral, 120 Degrees, Congruence, Midpoint, 60-120 degrees Rhombus, Polyiamond, DiamondAntonio Gutierrezhttp://www.blogger.com/profile/04521650748152459860noreply@blogger.comBlogger2125tag:blogger.com,1999:blog-6933544261975483399.post-66757103296947454562020-04-21T10:38:13.653-07:002020-04-21T10:38:13.653-07:00EF//BC//GH and FG//CD//EH so EFGH is a parallelogr...EF//BC//GH and FG//CD//EH so EFGH is a parallelogram and since EF = AB/2 = CD/2 = FG EFGH is a rhombus<br /><br />Further < EHG = 180 - (120-@) - @ = 60 and so EFGH is a 60-120 Rhombus<br /><br />Sumith Peiris<br />Moratuwa<br />Sri LankaSumith Peirishttps://www.blogger.com/profile/06211995240466447227noreply@blogger.comtag:blogger.com,1999:blog-6933544261975483399.post-87838961782061834152018-07-30T12:13:05.734-07:002018-07-30T12:13:05.734-07:00EF // GH, EF = FG => RhombusEF // GH, EF = FG => Rhombusc.t.e.onoreply@blogger.com