Geometry Problem 1528. Post your solution in the comment box below.

Level: Mathematics Education, K-12 School, Honors Geometry, College.

Details: Click on the figure below.

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ODQE is a square and hence < FQE = 45

ReplyDeleteBut QF = QE (radii of circle Q)

Therefore < QEF = <QFE = 67.5 degrees

Sumith Peiris

Moratuwa

Sri Lanka

90=<DQE=2<DCE, CD=CE by symmetry, so <QFE=90-<DCE/2=67.5

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