Geometry Problem 1517. Post your solution in the comment box below.

Level: Mathematics Education, K-12 School, Honors Geometry, College.

Details: Click on the figure below.

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V6 (sqrt of 6)

ReplyDeletehttps://photos.app.goo.gl/CkcFLDMpaKUyBK3a9

DeleteDrop perpendiculars DP and DQ from D to AB and from D to BC, P on AB and Q on BC respectively.

ReplyDeleteSince AD = DC, S(ABD) = S(BDC)

So AB.DP/2 = BC.DQ/2

Hence (c/2)d/(sqrt2) = (1/2).2. (sqrt3./2)d

Simplifying c = sqrt 6

Sumith Peiris

Moratuwa

Sri Lanka