Geometry Problem 1505. Post your solution in the comment box below.

Level: Mathematics Education, K-12 School, Honors Geometry, College.

Details: Click on the figure below.

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Draw line OD //L1

ReplyDeletewe have ^(COD)= 30 and ^(AOD)= 100 so ^(AOB)=^(BOC)= 35

so ^(OBL2)= 180- 65= 115

Let L3C meet OB at C1 and let L1A meet OB at A1

ReplyDeleteLet y = <COC1 = <AOA1

Now <OC1C = < B

Hence y + 80 = B....(1) and y + 30 + B = 180....(2)

(1) -(2) ; 80 - B - 30 = B - 180

Therefore x = 115

Sumith Peiris

Moratuwa

Sri Lanka