Saturday, January 30, 2016

Geometry Problem 1185: Similar Rectangles, Four Quadrilaterals, Sum of Areas, Metric Relations

Geometry Problem. Post your solution in the comment box below.
Level: Mathematics Education, High School, Honors Geometry, College.

Click the figure below to view more details of problem 1185.

Online Math: Geometry Problem 1185: Similar Rectangles, Four Quadrilaterals, Sum of the Areas, Metric Relations

Posted by Antonio Gutierrez at 8:46 PM
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4 comments:

  1. Peter TranJanuary 31, 2016 at 10:25 AM

    Draw new rectangle E’F’G’H’ similar to problem 1182
    Let k= AD/AB=EH/EF
    Let x= FF’=HH’ =>EE’=GG’=k.x
    All notations u, v,s, t , S(XYZ) will be the same as problem 1182
    Perform length and width comparison of 2 similar rectangles ABCD and EFGH we will get
    (u+v+x)/(t+s+k.x)= k …… (1)
    Similar to pro. 1182 we have a^2+c^2= u^2+v^2+s^2+t^2+2k.x(k.x+t+s)…..(2)
    And b^+d^2= u^2+v^2+s^2+t^2+2x(x+u+v)…..(3)
    Replace expression (1) in (2) we will get a^2+c^2=b^2+d^2

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    Replies
    1. Peter TranFebruary 3, 2016 at 11:13 PM

      http://s25.postimg.org/5ag8xy18f/pro_1185_2.png
      See below for solution of problem 1185 part 2
      From midpoint of each side of rectangle EFGH draw a new rectangle (red) with each side parallel to rectangle ABCD.
      Define u’, v’, s’, t’ , z, w as shown on the sketch
      Note that this red rectangle is similar to rect. ABCD and
      (u’+v’)/(s’+t’)= AD/AB= z/w ….. (4)
      At each corner of ABCD we have 2 equal areas triangles so the problem become to show that trapezoids areas of (S1+S3)= trapezoids areas of ( S2+S4).
      Trapezoids areas of (S1+S3)= w(u’+v’)
      And trapezoids areas of ( S2+S4).= z(s’+t’).
      Using relation of (4) in above expressions we will get S1+S3=S2+S4

      Delete
  2. c.t.e.oJanuary 31, 2016 at 11:10 AM

    Second half of solution
    draw EE' perpendicular to AB and EE`` to AD.At the same way from F,G,H
    Trapezoids EFF'E', GHH``G`` have altitude E'F' trapezoids FGF``G`` and EHH``E``
    have altitude E``H``. Ratio E'F'/E``H``= AB/AD = EF/FH (similar tr with perp sides)
    Sum of their bases are in ratio AD/AB=FH/EF (as diferences of inverse ratio)
    First part of solutions is clear acording to pythaghor theorem included ratios
    above

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  3. c.t.e.oFebruary 4, 2016 at 9:33 AM

    Sum of S of trapezoids (' on AB,CD, " on AD, BC)
    E"H"(AB-E'F'+AB-E'F')=? E'F'(AD-E"H"+AD-E"H")
    E"H"AB-E"H"E'F' =? E'F'AD-E'F'E"H"
    E"H"AB =? E'F'AD
    AB/AD = E'F'/E"H"

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