Friday, January 29, 2016

Geometry Problem 1183: Parallelogram, Diagonals, Circle, Tangent Line

Geometry Problem. Post your solution in the comment box below.
Level: Mathematics Education, High School, Honors Geometry, College.

Click the figure below to view more details of problem 1183.

Online Math: Geometry Problem 1183: Parallelogram, Diagonals, Circle, Tangent Line

2 comments:

  1. Let AC meet BD at H
    Observe that radius of circle A= radius of circle C
    so AE=CF => HE=GF
    H is the midpoint of EF and BD => EBFD is a parallelogram

    ReplyDelete
  2. tr ABD congr tr CBD =>altitudes A to tg point congr to C to tg point
    => Ra=Rb => EA=CF =>BD and EF halve each other

    ReplyDelete