Geometry Problem. Post your solution in the comment box below.
Level: Mathematics Education, High School, Honors Geometry, College.
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Friday, January 29, 2016
Geometry Problem 1183: Parallelogram, Diagonals, Circle, Tangent Line
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Let AC meet BD at H
ReplyDeleteObserve that radius of circle A= radius of circle C
so AE=CF => HE=GF
H is the midpoint of EF and BD => EBFD is a parallelogram
tr ABD congr tr CBD =>altitudes A to tg point congr to C to tg point
ReplyDelete=> Ra=Rb => EA=CF =>BD and EF halve each other