Geometry Problem
Level: Mathematics Education, High School, Honors Geometry, College.
Click the figure below to see the complete problem 930.
Friday, September 27, 2013
Geometry Problem 930: Acute Triangle, Altitudes, Circles, Diameter, Angle, Measure
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ReplyDeletenote that BFDC is cyclic quadrilateral => AF.AB=AD.AC
but AF.AB=AG^2 and AD.AC=AE^2… ( relation in right triangles AGB and AEC)
so AG=AE=AH
draw circle centered A, radius=AG
Observe that ∠ (HGE)= ½∠ (HAE)= ½(180-2*55)= 35 degrees
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