Tuesday, May 14, 2013

Problem 875: Congruent Circles, Intersecting Circles, Secant, Center, Angle Trisection, Triple Angle, Triangle

Geometry Problem. Post your solution in the comments box below.
Level: Mathematics Education, High School, Honors Geometry, College.

Click the figure below to see the complete problem 875.

Online Geometry Problem 875: Congruent Circles, Intersecting Circles, Secant, Center, Angle Trisection, Triple Angle, Triangle

Posted by Antonio Gutierrez at 1:23 PM
Labels: , , , , , , , ,

3 comments:

  1. UnknownMay 14, 2013 at 1:47 PM

    build BC
    BC=AC
    CBA=A=a
    BCE=2a
    BC=BE
    E=BCE=2a
    EBF=E+A=3a
    q.e.d

    ReplyDelete
  2. Jacob HA (EMK2000)May 14, 2013 at 5:29 PM

    Join BC. Then AC = BC = BE.

    β = α + ∠BEA
    = α + ∠BCE
    = α + α + ∠CBA
    = α + α + α
    = 3α

    ReplyDelete
  3. Falensius NangoMay 14, 2013 at 10:46 PM

    Draw a line from point B to C.
    Triangle ABC is an isosceles triangle, AC = BC, then ∠CAB = ∠CBA.
    ∠BCE = 2α.
    in triangle ABE if ∠AEB is x then ∠EBF is exterior angle, then β = α + x
    ∠BCE = ∠AEB = 2α then β = α + 2α = 3α (q.e.d)

    ReplyDelete

Subscribe to: Post Comments (Atom)