Geometry Problem
Click the figure below to see the complete problem 610.
Monday, May 30, 2011
Problem 610: Intersecting Circles, Radius, Parallel, Common Tangent, Angle, 90 Degrees
Subscribe to:
Post Comments (Atom)
Geometry Problem
Click the figure below to see the complete problem 610.
AG/GB =AE/BF=AC/BC
ReplyDeleteSo CG bisects angle ACB internally
AH parallel BM
AN/BN = AH/BM =AC/BC
So CH bisects angle ACB externally
Therefore angle GCH = 90 degrees