See complete Problem 113
Area of Triangles, Incircle, Excircles. Level: High School, SAT Prep, College geometry
Post your solutions or ideas in the comments.
Tuesday, June 3, 2008
Elearn Geometry Problem 113
Subscribe to:
Post Comments (Atom)
MA=BF=p-c
ReplyDeleteDA=CG=p-b
CH=BE=p-a
all triangles have altitude r
S1=S1'=0.5r(p-b)
S2=S2'=0.5r(p-a)
S3=S3'=0.5r(p-c)
.-.
AD = CG = s - AC ...........(s = 1/2 perimeter)
ReplyDelete[IAD]= 1/2 . r . AD .......( r = inradius )
[ICG]= 1/2 . r . CG .......( r = inradius )
obviuos that [IAD] = [ICG]
With the same way , can be proved that :
[IBE]=[ICH]and [IBF]=[IAM]
Teddy A D (wteddyad@yahoo.com)