See complete Problem 99
Circle Area, General Extension to Pythagoras' Theorem. Level: High School, SAT Prep, College geometry
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Monday, May 19, 2008
Geometry Problem 99
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If we take the area of semicricle with diameter AO as x and semicircle woth diameter DC as y, then by pythagoras theorem on the trianle ABC, we can say that
ReplyDeleteS+x=S1+S2+y
Now using the pythagoras theorem in right angled triangle DOC,
We can say that
y=x+S3
putting this value of y in above equation we can prove that
S=S1+S2+S3