Monday, May 19, 2008

Geometry Problem 99



See complete Problem 99
Circle Area, General Extension to Pythagoras' Theorem. Level: High School, SAT Prep, College geometry

Post your solutions or ideas in the comments.

1 comment:

  1. If we take the area of semicricle with diameter AO as x and semicircle woth diameter DC as y, then by pythagoras theorem on the trianle ABC, we can say that
    S+x=S1+S2+y

    Now using the pythagoras theorem in right angled triangle DOC,
    We can say that
    y=x+S3

    putting this value of y in above equation we can prove that

    S=S1+S2+S3

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