See complete Problem 56
Tangent Circles, Angle Bisector, Parallel. Level: High School, SAT Prep, College geometry
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Monday, May 19, 2008
Elearn Geometry Problem 56
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ang CBG = ang QPG (1)( GQPB cyclic,arc GQ, see P 55 )
ReplyDeleteang CDG = ang CBG (2)( CDBG cyclic, arc CG )
from (1) & (2)
CDG = QPG
& as corresponding angles
=>
CD//PQ