Proposed Problem

See complete Problem 267 at:

gogeometry.com/problem/p267_right_triangle_catheti_product.htm

Level: High School, SAT Prep, College geometry

## Thursday, March 12, 2009

### Problem 267: Right Triangle, Product of Catheti

Labels:
altitude,
cathetus,
hypotenuse,
right triangle,
similarity

Subscribe to:
Post Comments (Atom)

Area of Tr. ABC = (1/2)*c*h

ReplyDeleteSince BC is perpendicular to AC,area of Tr. ABC is also=(1/2)*b*c. Thus (1/2)*c*h = =(1/2)*b*c

or a*b = c*h

Ajit: ajitathle@gmail.com

like P 266

ReplyDeleteTypo Correction

ReplyDeleteThe second line in my proof above should've read:

Since BC is perpendicular to AC, area of Tr. ABC is also=(1/2)*a*b. Thus (1/2)*c*h = =(1/2)*a*b

Ajit

Triangles ABC and ACH are similar therefore :

ReplyDeletea/c=h/b

ab=ch