See complete Problem 99

Circle Area, General Extension to Pythagoras' Theorem. Level: High School, SAT Prep, College geometry

Post your solutions or ideas in the comments.

## Monday, May 19, 2008

### Geometry Problem 99

Labels:
area,
circle,
Pythagoras

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If we take the area of semicricle with diameter AO as x and semicircle woth diameter DC as y, then by pythagoras theorem on the trianle ABC, we can say that

ReplyDeleteS+x=S1+S2+y

Now using the pythagoras theorem in right angled triangle DOC,

We can say that

y=x+S3

putting this value of y in above equation we can prove that

S=S1+S2+S3