Challenging Geometry Puzzle: Problem 1601. Share your solution by posting it in the comment box provided.
Audience: Mathematics Education - K-12 Schools, Honors Geometry, and College Level.
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< ABP = < ACD = < DPJ = < BPK
ReplyDeleteHence KB = KP and so K is the midpoint of AB
Similarly for M,F,H
Hence KM//AC//HF and KH // BD//MF and so
KMFH is a parallelogram
Since AC is perpendicular to BD it follows that
KMFH is a Rectangle
Sumith Peiris
Moratuwa
Sri Lanka