Challenging Geometry Puzzle: Problem 1556. Share your solution by posting it in the comment box provided.

Audience: Mathematics Education - K-12 Schools, Honors Geometry, and College Level.

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Since < OEF = < EBG, Triangles EOF & EBG are congruent (ASA)

ReplyDeleteSo GE = OF = 1

But EF = DE / 2 = 8 /2 = 4

Therefore FG = EF - GE = 4 - 1 = 3

Sumith Peiris

Moratuwa

Sri Lanka