Geometry Problem 1532. Post your solution in the comment box below.

Level: Mathematics Education, K-12 School, Honors Geometry, College.

Details: Click on the figure below.

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Let M is the midpoint of AD

ReplyDeletesince TD ⊥MC => ∡ (CTD)=∡ (CDT)=∡ (CMD)

∡ (CMD)= atan(CD/MD) =atan(2)~63.43 degrees

Let O be the mid point of AD.

ReplyDeleteThen OTCD is a kite and < TCO = < DCO = arctan (1/2).

So ? = 90 - arctan (1/2)

90 - arctan (1/2) is the same as arctan(2) = 63.4 degrees approximately

DeleteBT/AT = sqrt2 is another result from this problem

ReplyDeleteAlso BT bisects the Right Angle ATD

Delete