Geometry Problem 1485. Post your solution in the comment box below.
Level: Mathematics Education, K-12 School, Honors Geometry, College.
Details: Click on the figure below.
Wednesday, November 25, 2020
Geometry Problem 1485: Triangle, Orthocenter, Altitude, Circle, Diameter, Tangent, Measurement
Labels:
altitude,
circle,
diameter,
geometry problem,
measurement,
orthocenter,
tangent,
triangle
Subscribe to:
Post Comments (Atom)
https://photos.app.goo.gl/v7KgdZECAesRBJjr9
ReplyDeleteDraw altitude BD of triangle ABC ( see sketch)
We have B, H, D are collinear ( H is the orthocenter)
Quadrilateral ADEB is cyclic so HE.HA=HB.HD= 140
In cycle BTDC we have HT.HF=HB.HD=140
So HF= 140/HT=8.5
minor correction of the last line:
DeleteSo HF= 140/HT=8.75
Draw altitude BP
ReplyDeleteWe have BH . HP = 140
=> TH . HF = 140 => HF = 8.75
https://photos.app.goo.gl/7F46Z7YkTbVG5kkk9
Delete