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Level: Mathematics Education, High School, Honors Geometry, College.
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Saturday, March 21, 2020
Dynamic Geometry Problem 1464: Quadrilateral, Interior Point, Midpoint of Sides, Equal Sum of Areas
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From the midpoint theorem,
ReplyDeleteEF//AC//GH and FG//BD//EH so EFGH is a parallelogram and by Problem 1463,
S(PEF) + S(PGH) = S(PFG) + S(PEH) ....(1)
Now S(ABCD) = S(ABC) + S(ACD) = 4.S(BEF) + 4.S(DGH) ...(2)
Similary S(ABCD) = S(ABD) + S(BCD) = 4.S(AEH) + 4.S(CFG) ....(3)
From (2) & (3), S(BEF) + S(DGH) = S(CFG) + S(AEH) ...(4)
Add (1) + (4)
S2 + S4 = S3 + S1
Sumith Peiris
Moratuwa
Sri Lanka
APE(=PEB+)+APH(=PHD+)+CPG(=GPD+)+CPF(=FPB+)
ReplyDelete=> S yellow(=S green)
Good solution, much simpler than mine
DeleteThanks you are big favorite of me for your solutions
DeleteThank u. Same here!
DeleteP1465
ReplyDeleteAE=AH, BE=BF, CG=FC, DG=DH => AE+BE+CG+DG=AH+BF+FC+DH =>
(AE+BE+CG+DG).R =(AH+BF+FC+DH).R
S yellow = S green