Interactive step-by-step animation using GeoGebra. Post your solution in the comment box below.
Level: Mathematics Education, High School, Honors Geometry, College.
Details: Click on the figure below.
Saturday, December 7, 2019
Dynamic Geometry 1451: Orthopole of a Line
Subscribe to:
Post Comments (Atom)
https://photos.app.goo.gl/KnTd7PoVyZg2faVS7
ReplyDeleteLet A’A’’ meet B’B” at P
And C’C’’ meet B’B” at Q ; BB’ meet AC at D
Triangle BDC similar to A’B’P ( case AA)
So DC/B’P= BD/A’B’ => B’P= DC x A’B’/ BD
Triangle BDA similar to C’B’Q ( case AA) => B’Q=DA x C’B’/BD
Since AA’//BB’//CC’ => DC x A’B’= DA x C’B’
So B’P=B’Q => P coincide to Q