Geometry Problem. Post your solution in the comment box below.

Level: Mathematics Education, High School, Honors Geometry, College.

Details: Click on the figure below.

## Sunday, June 9, 2019

### Geometry Problem 1439: Rectangle, Diagonal, Perpendicular, Circles, Areas

Labels:
area,
circle,
diagonal,
geometry problem,
perpendicular,
rectangle,
right triangle

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From Pythagoras,

ReplyDeleteCD^2 = CE^2 - DE^2 = BD^2 - BC^2 and so

BD^2 + DE^2 = BC^2 + CE^2

Hence S1 + S4 = S2 + S3

Sumith Peiris

Moratuwa

Sri Lanka