Geometry Problem. Post your solution in the comment box below.
Level: Mathematics Education, High School, Honors Geometry, College.
Details: Click on the figure below.
Sunday, June 9, 2019
Geometry Problem 1439: Rectangle, Diagonal, Perpendicular, Circles, Areas
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From Pythagoras,
ReplyDeleteCD^2 = CE^2 - DE^2 = BD^2 - BC^2 and so
BD^2 + DE^2 = BC^2 + CE^2
Hence S1 + S4 = S2 + S3
Sumith Peiris
Moratuwa
Sri Lanka