Geometry Problem. Post your solution in the comment box below.

Level: Mathematics Education, High School, Honors Geometry, College.

Details: Click on the figure below.

## Saturday, May 18, 2019

### Geometry Problem 1434: Equilateral Triangle, Tangent Circles, Tangent Lines, Arithmetic Mean, Measurement

Labels:
arithmetic mean,
circle,
equilateral,
geometry problem,
inscribed,
measurement,
tangent,
triangle

Subscribe to:
Post Comments (Atom)

https://photos.app.goo.gl/hawHpVWSb5MK1TVcA

ReplyDeleteLet BO meet AC at P and circle O at Q

Since ABC is equilateral , ^(AOC)=120 => P is the midpoint of OQ

Per the result of problem 1433 we have

BN=2.PF and BM=2.PD

So BM+BN=2(PF+PD)=2.DF

Trough BO, make diameter BH, H on circomference,intersect with AC at K,

ReplyDeleteFrom 1433, BN= 2 KF,

BM=2DK,

so BM+BN= 2(DF)