Geometry Problem. Post your solution in the comment box below.
Level: Mathematics Education, High School, Honors Geometry, College.
Details: Click on the figure below.
Friday, March 22, 2019
Geometry Problem 1427: Circle inscribed in a square, Arc, Tangent Line, Tangent Circles, Radii
Labels:
arc,
circle inscribed,
geometry problem,
radius,
square,
tangent
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Let the square be of side 2a.
ReplyDeleteDenote sqrt2 by p.
Then pr1 + r1 = 2p.a - 2a
So r1 = 2(p-1)/(p+1)a.....(1)
Also p.r2 + r2 + a = p.a
Hence r2 = (p-1)/(p+1)a ....(2)
From (1) and (2)
r1 = 2.r2
Sumith Peiris
Moratuwa
Sri Lanka
https://photos.app.goo.gl/bzbDb5w5sQ24aZnf6
ReplyDeleteLet AB=AD=2.a
We have CE=AC-AE=2a.(sqrt(2)-1)= O1E+O1C= r1(1+sqrt(2))
So r1= 2a(sqrt(2)-1) ^2
Similarly we also have r2= a(sqrt(2)-1) ^2
So r1= 2 r2
https://photos.app.goo.gl/V4sKjMDJsFrQDuMBA
DeleteNew approach to solve this problem
Let O3 is the circle shown on the sketch
Obviously r3=r2
perform homothety transformation center C, factor= 2.
Circle O will become circle A radius AB. Lines BC and CD will be the same
O3 become circle O1
So r1=2r3=2r2
From AO => R(√2-1) = r2(√2+1)
ReplyDeleteFrom AC => 2R(√2-1) = r1(√2+1)
r2 is the radius of a circle tangent to a square with side D and its incircle
ReplyDeletethen 2r2 is the radius of a circle tangent to a square with side 2D and its incircle
Therefore r1=2r2