Monday, March 4, 2019

Geometry Problem 1420: Regular Hexagon, Inscribed Circle, Area, Tangent

Geometry Problem. Post your solution in the comment box below.
Level: Mathematics Education, High School, Honors Geometry, College.

Details: Click on the figure below.

Geometry Problem 1420: Regular Hexagon, Inscribed Circle, Area, Tangent, Tutoring.

3 comments:

  1. From ∆CHE => R(G) = (3r√3)/2 r = r(Q)
    => S = 27

    ReplyDelete
  2. Let the side of the regular hexagon be a. We note that B,H,O,G,E are collinear.

    BE = 2a and BH = a/2 so EG = 3a/4 and r(Q)^2 = (9/16).a^2

    S(G)/S(Q) = r(G)^2/r(Q)^2 = (a^2*(9/16)) / (a^2/12) = 6.75
    So S(G) = 18

    Sumith Peiris
    Moratuwa
    Sri Lanka

    ReplyDelete
    Replies
    1. Got the geometry right and the arithmetic wrong!

      6.75 X 4 is indeed 27 not 18

      Delete