Wednesday, August 29, 2018

Geometry Problem 1382: Circle, Diameter, Radius, Perpendicular, Congruence

Geometry Problem. Post your solution in the comment box below.
Level: Mathematics Education, High School, Honors Geometry, College.

Details: Click on the figure below.

Geometry Geometry Problem 1382: Circle, Diameter, Radius, Perpendicular, Congruence.

6 comments:

  1. Angle COG = Angle FPE = 180 - Angle BOC
    E, O, F, P, are on the circle with center O1 and diameter OP
    Connect F with O1, and this line intersects the circle with center O1 at L.
    FL = OP = OC
    Angle FLE = Angle FPE
    triangle OCG = triangle FLE
    CG = EF

    Erina NJ

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  2. https://photos.app.goo.gl/HnS668zUQ5v6RaBC9

    Note that quadr. OEPF is cyclic
    So ∠ (FOA)= ∠ (FPE)= u
    Draw PN ⊥ EF , N is the intersection of FN to circle OEPF
    Note that NE and OP are diameters of circle OEPF
    And ∠ (FNE)= ∠ (FPE)= u
    Triangle OCG congruent to ENF ( case HA) so CG= EF

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    Replies
    1. Thank you for the picture of the geometry problem, and the comment you made to my solution.

      Delete
  3. Note that F,O,E,P concylic, so by Sine rule, EF = OPsin<P = OCsin<COG = CG. done
    Alex Toronto

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