Saturday, July 28, 2018

Geometry Problem 1367: Equilic Quadrilateral, 120 Degrees, Congruence, Midpoint, Diagonal, Equilateral Triangle

Geometry Problem. Post your solution in the comment box below.
Level: Mathematics Education, High School, Honors Geometry, College.

Details: Click on the figure below.

Geometry Problem 1367: Equilic Quadrilateral, 120 Degrees, Congruence, Midpoint, Diagonal, Equilateral Triangle.

Posted by Antonio Gutierrez at 10:34 AM
Labels: , ,

2 comments:

  1. c.t.e.oJuly 28, 2018 at 12:28 PM

    Extend AB and DC to P. Extend EF to Q, (on DP)
    Ang APD= ang EQD= ang EFG = 60°

    ReplyDelete
  2. Sumith PeirisJuly 31, 2018 at 8:39 AM

    Follows easily from the mid point theorem.

    EF // AB & FG // CD

    AB & CD cut at 60 so must EF & FG.

    EF = AB/2 = CD / 2 = FG

    So Tr. EFG is isocleles with an angle 60 so it must be equilateral

    Sumith Peiris
    Moratuwa
    Sri Lanka

    ReplyDelete

Share your solution or comment below! Your input is valuable and may be shared with the community.

Subscribe to: Post Comments (Atom)