Saturday, July 28, 2018

Geometry Problem 1367: Equilic Quadrilateral, 120 Degrees, Congruence, Midpoint, Diagonal, Equilateral Triangle

Geometry Problem. Post your solution in the comment box below.
Level: Mathematics Education, High School, Honors Geometry, College.

Details: Click on the figure below.

Geometry Problem 1367: Equilic Quadrilateral, 120 Degrees, Congruence, Midpoint, Diagonal, Equilateral Triangle.

Posted by Antonio Gutierrez at 10:34 AM
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2 comments:

  1. c.t.e.oJuly 28, 2018 at 12:28 PM

    Extend AB and DC to P. Extend EF to Q, (on DP)
    Ang APD= ang EQD= ang EFG = 60°

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  2. Sumith PeirisJuly 31, 2018 at 8:39 AM

    Follows easily from the mid point theorem.

    EF // AB & FG // CD

    AB & CD cut at 60 so must EF & FG.

    EF = AB/2 = CD / 2 = FG

    So Tr. EFG is isocleles with an angle 60 so it must be equilateral

    Sumith Peiris
    Moratuwa
    Sri Lanka

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