Geometry Problem. Post your solution in the comment box below.

Level: Mathematics Education, High School, Honors Geometry, College.

Details: Click on the figure below.

## Saturday, July 28, 2018

### Geometry Problem 1367: Equilic Quadrilateral, 120 Degrees, Congruence, Midpoint, Diagonal, Equilateral Triangle

Labels:
equilateral,
equilic quadrilateral,
midpoint

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Extend AB and DC to P. Extend EF to Q, (on DP)

ReplyDeleteAng APD= ang EQD= ang EFG = 60°

Follows easily from the mid point theorem.

ReplyDeleteEF // AB & FG // CD

AB & CD cut at 60 so must EF & FG.

EF = AB/2 = CD / 2 = FG

So Tr. EFG is isocleles with an angle 60 so it must be equilateral

Sumith Peiris

Moratuwa

Sri Lanka