Geometry Problem. Post your solution in the comment box below.

Level: Mathematics Education, High School, Honors Geometry, College.

Details: Click on the figure below.

## Tuesday, July 17, 2018

### Geometry Problem 1366: Square, Angle Bisector, Perpendicular, Concyclic Points, Circle, Sketch, iPad Apps.

Labels:
angle bisector,
circle,
concyclic,
drawing,
geometry problem,
perpendicular,
sketch,
square

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This follows very easily from my problem 1363 since < AHB = < ADB = 45

ReplyDeleteSumith Peiris

Moratuwa

Sri Lanka

https://photos.app.goo.gl/perU7VCwHMwg3bCF8

ReplyDeleteConnect BD and draw altitude BK of triangle ABG

Triangle BGF congruent to BCF ( case ASA)

So BG=BC=BA

In isosceles triangle ABG, AK is altitude and an angle bisector

So ∠ (KBH)=1/2. ∠ (ABC)= 45 degrees => ∠ (BHK)= 45

Since ∠ (BDA)= ∠ (BHA)= 45 => B, H, D, A are cocyclic with AD as a diameter

So A,B,C,H,D are cocyclic

Is A,B,C,H,D=concyclic.

ReplyDeletetest

ReplyDelete