Thursday, February 23, 2017

Geometry Problem 1318: Rectangle, Equilateral Triangle, Distances, Perpendicular, Measurement

Geometry Problem. Post your solution in the comment box below.
Level: Mathematics Education, High School, Honors Geometry, College.

Details: Click on the figure below.

Geometry Problem 1318: Rectangle, Equilateral Triangle, Distances, Perpendicular, Measurement.

Posted by Antonio Gutierrez at 10:08 AM
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2 comments:

  1. APOSTOLIS MANOLOUDISFebruary 23, 2017 at 11:05 AM

    Problm 1318
    Let that the area of the triangle ABC is (ΑΒC) then apply that (ΑΕF)=(CBE)+(CFD) or
    (EF.AH)/2=(CE.BG)/2+(CF.DM)/2 or AH=BG+DM or x=22-7=15.
    APOSTOLIS MANOLOUDIS KORYDALLOS PIRAEUS GREECE

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  2. Sumith PeirisFebruary 23, 2017 at 1:03 PM

    Following on from my proof for Problem 969 easily

    S1 = S2 + S3

    All 3 triangles have an equal base.

    Hence x = 22-7= 15

    Sumith Peiris
    Moratuwa
    Sri Lanka

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