In the triangle ABC, we know the centroid G divides Orthocenter H and Circumcenter O in the ratio 2:1 The Medal triangle MaMbMc is similar to ABC but its centroid remains the same i.e G We can see that Ma is projection of A along the lines BMb, CMc and similarly Mb is projection of B and Mc is projection of C Hence O is the projection of H along the lines passing through the centroid.
So in the Medal triangle, O is the orthocenter and N is the circumcenter Hence OG = 2NG => If NG = 1 => OG = 2 => NO = NG+GO = 3 But GH = 2OG => GH = NG + NH = 2*2 = 4 => NH = 4-1=3
Hence center of the Nine point circle of triangle ABC is the midpoint of the Euler line
In the triangle ABC, we know the centroid G divides Orthocenter H and Circumcenter O in the ratio 2:1
ReplyDeleteThe Medal triangle MaMbMc is similar to ABC but its centroid remains the same i.e G
We can see that Ma is projection of A along the lines BMb, CMc and similarly Mb is projection of B and Mc is projection of C
Hence O is the projection of H along the lines passing through the centroid.
So in the Medal triangle, O is the orthocenter and N is the circumcenter
Hence OG = 2NG => If NG = 1 => OG = 2 => NO = NG+GO = 3
But GH = 2OG => GH = NG + NH = 2*2 = 4 => NH = 4-1=3
Hence center of the Nine point circle of triangle ABC is the midpoint of the Euler line