Geometry Problem. Post your solution in the comments box below.
Level: Mathematics Education, High School, Honors Geometry, College.
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Wednesday, October 14, 2015
Geometry Problem 1153: Triangle, Angle Bisectors, Perpendicular, Congruence
Labels:
angle bisector,
congruence,
perpendicular,
triangle
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Let I is incenter of triangle ABC
ReplyDeleteLet BI meet AC at L
Observe that EBDI is a complete quadrangle so L, F are harmonic conjugate points of A and C.
Since BL is an internal bisector of angle ABC So BL is external bisectors of angle ABC and FH=FG
this problem need
ReplyDelete1) BF bisector of CBH
2) IBF = 90
3) BI // GH
4) GB = BH
It is possible in another construcsion included AB > BC