Geometry Problem. Post your solution in the comments box below.
Level: Mathematics Education, High School, Honors Geometry, College.
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Thursday, July 2, 2015
Geometry Problem 1126: Equilateral Triangle, Circumcircle, Metric Relation, Harmonic Mean
Labels:
circumcircle,
equilateral,
harmonic mean,
metric relations,
similarity,
triangle
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Observe that ∠ADB=∠ADE=60°,
ReplyDeletethus from S(ADB)+S(ADE)=S(BDE),
xe sin60° + xd sin60° = de sin120°
x=de/(d+e)
x/d=BC/EB=AB/EB=1/(EB/AB)=1/(1+d/e)=e/(e+d)
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