Geometry Problem. Post your solution in the comment box below.
Level: Mathematics Education, High School, Honors Geometry, College.
Click the diagram below to enlarge it.
Saturday, March 14, 2015
Geometry Problem 1098: Circles, Common External Tangent, Common Internal Tangent, Radius, Metric Relations
Labels:
circle,
common tangent,
metric relations,
radius
Subscribe to:
Post Comments (Atom)
Obvious ∠O₁CO₂=90°, thus ∠O₁CA₁ + ∠O₂CA₂=90°.
ReplyDeleteThat is, ΔO₁CA₁~ΔCO₂A₂.
Hence, O₁A₁/CA₂ = CA₁/O₂A₂.
i.e. r₁×r₂ = A₁C×A₂C.