Geometry Problem. Post your solution in the comments box below.
Level: Mathematics Education, High School, Honors Geometry, College.
Click the diagram below to enlarge it.
Saturday, November 8, 2014
Geometry Problem 1058: Triangle, Sum of the Areas, Altitude, Perpendicular, Circumcircle, Circle, Diameter
Labels:
altitude,
area,
circle,
circumcircle,
diameter,
perpendicular,
triangle
Subscribe to:
Post Comments (Atom)
One can show that BD⊥EF.
ReplyDeleteThen
S(BEDF)
= 1/2×BD×EF
= BO×EF
= S(ABC) (by Problem 1055)
Thus sobtracting S(BEGMF) both side,
S₁+S₂=S₃
Join DA, DC,DH. Let (XYZ) stand for area of ΔXYZ.
ReplyDeleteAD // EH implies (AED) = (AHD). Follows S1 = (GHD).
DC // HF implies (DFC) = (DHC). Follows S2 = (MHD).
Hence S1 + S2 = S3.