Geometry Problem. Post your solution in the comments box below.
Level: Mathematics Education, High School, Honors Geometry, College.
Click the figure below to view the complete problem 1039.
Saturday, August 23, 2014
Geometry Problem 1039: Isosceles Triangle, Circle, Tangent Line, Parallel Line
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Join AD.
ReplyDeleteSince ∠FCB = ∠EDB = ∠EAD,
so A,C,D,F are concyclic.
Since ∠FAC = ∠DCA = ∠BFD,
thus FD//AC.
< FCD = < BDE = < DAE hence ACDF is cyclic so < EDF = < CFD = < CAD = < ACF since < BAC = < ACB and < DAF = DCF
ReplyDeleteHence FD // AC
Sumith Peiris
Moratuwa
Sri Lanka