Geometry Problem. Post your solution in the comments box below.
Level: Mathematics Education, High School, Honors Geometry, College.
Click the figure below to view the complete problem 1037.
Saturday, August 2, 2014
Geometry Problem 1037: Triangle, Three equal Incircles, Tangent lines, Inradius, Length
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Let r2 is the inradius of triangle A2B2C2
ReplyDeleteNote that incenter of triangle ABC is coincided to incenter of triangle A2B2C2
So r=d+r2
But r2=r1 per problem 1036
So r1= r-d