Geometry Problem
Level: Mathematics Education, High School, Honors Geometry, College.
Click the figure below to see the complete problem 965.
Wednesday, January 22, 2014
Geometry Problem 965: Triangle, Cevians, Midpoint, Circumcircle, Circle, Tangent Line, Metric Relations
Labels:
cevian,
circle,
circumcircle,
metric relations,
midpoint,
tangent,
triangle
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we have FH= 25/2=12.5 and FH//CD
ReplyDeleteFG//EA and FG= .5*EA
And ∠ (GHF)= ∠ (EFG)= ∠ (BEF)
Triangle GFH similar to DBE ….( case AA)
FH/EB=FG/BD => FG=12.5 x 14/40= 4.375
So EA= 8.75