Geometry Problem. Post your solution in the comments box below.
Level: Mathematics Education, High School, Honors Geometry, College.
Click the figure below to enlarge the problem 944.
Wednesday, December 18, 2013
Geometry Problem 944: Triangle, Orthocenter, Altitude, Perpendicular, 90 Degrees, Parallel Lines
Subscribe to:
Post Comments (Atom)
Since FE//GK, so HE/HK = HF/HG.
ReplyDeleteSince FJ//ED, so HF/HG = HJ/HD.
Thus, HE/HK = HJ/HD, hence JE//DK.
Correction: FJ//GD in line 2.
Delete<FHJ=<FEJ=<GKD of cyclic quadrilaterals FJEH and GDKH. But EF//GK so JE//DK.
ReplyDelete