Saturday, August 10, 2013

Problem 911: Right Triangle, Double Angle, Triple Angle, Concyclic Points, Cyclic Quadrilateral

Geometry Problem
Post your solution in the comment box below
Level: Mathematics Education, High School, Honors Geometry, College.

Click the figure below to see the complete problem 911.

Online Geometry Problem 911: Right Triangle, Double Angle, Triple Angle, Concyclic Points, Cyclic Quadrilateral.

Posted by Antonio Gutierrez at 8:14 AM
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3 comments:

  1. Jacob HA (EMK2000)August 10, 2013 at 1:59 PM

    In ΔABC and ΔBCD,
    ∠BCA = 90° − 2α
    ∠BDC = 90° − 3α

    In ΔBCE,
    ∠EBC = 90°
    ∠BEC = 90° − 3α = ∠BDC

    Hence, B, C, D, E concyclic.

    ReplyDelete
  2. Sumith PeirisOctober 6, 2015 at 12:59 AM

    < EBD = 90- @ = < ECD since < BCD = 90 + 2@ and so the result follows

    Sumith Peiris
    Moratuwa
    Sri Lanka

    ReplyDelete
  3. Sailendra TFebruary 10, 2021 at 10:58 AM

    Triangles ABD and ACE similar => AB.AE=AC.AD

    ReplyDelete

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