Geometry Problem. GeoGebra, HTML5 Animation for iPad and Nexus.
Post your solution in the comments box below.
Level: Mathematics Education, High School, Honors Geometry, College.
Click the figure below to see the dynamic geometry demonstration of problem 896.
Thursday, July 4, 2013
Problem 896: Triangle, Orthocenter, Midpoint, Median, Intersecting Circles, Diameter, Collinear Points
Labels:
collinear,
diameter,
intersecting circles,
midpoint,
orthocenter,
triangle
Subscribe to:
Post Comments (Atom)
quadrilateral BIJC is cyclic
ReplyDeleteSo HB.HJ=HI.HC
But HB.HJ= power of H to circle D
And HI.HC is the power of H to circle E
So H must be on axis of equi-power of circles D and E
F, H and G are collinear