Geometry Problem. Post your solution in the comments box below.
Level: Mathematics Education, High School, Honors Geometry, College.
Click the figure below to see the complete problem 891.
Sunday, June 23, 2013
Problem 891: Equiangular Octagon, Metric Relations, Sides, Auxiliary Lines
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Distance between DE & AH = 6+5 = 7+x
ReplyDeletex = FG = 4
Like Jacob Ha, I extended DE, BC, AH and GF
ReplyDeleteDE line meet BC line at W
DE line meet GF line at T
AH and FG at U
and AH and BC at K
WTUK is a rectangle [easy to prove]
WK=TU
WK=d/sqrt(2)+5+a/sqrt(2)
TU=c/sqrt(2)+d/sqrt(2)+x
6+5=x+7
x=4
that was really helpful
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