Geometry Problem
Level: Mathematics Education, High School, Honors Geometry, College.
Click the figure below to see the complete problem 855.
Saturday, February 9, 2013
Problem 855: Quadrilateral, Triangle, Angles, 30 degrees, Congruence, Auxiliary lines
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The perpendicular from point B, to the AC meet AD at point E. Because AC, it's height and bisector of the triangle ABE, is isosceles. So, angle AEB= 77 degrees. The triangle BEC , is equilateral. So ,angle DBE =86-60=26 degrees ,therefore angle BDE=77 degrees .Then, BD=BE=BC .So ,from the triangle BDC , 86+2(30+X)=180 .So, x=17 degrees
ReplyDeletePlan: http://img832.imageshack.us/img832/3616/p855triangleangle30degr.gif
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ReplyDeleteFie ABE un triungi isoscel AB=AE cu m( x= 30-13=17
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