Sunday, January 27, 2013

Problem 849: Special Right triangle, Catheti or legs ratio 1:3, 18.5 Degrees, Double angle

Geometry Problem
Level: Mathematics Education, High School, Honors Geometry, College.

Click the figure below to see the complete problem 849.

Online Geometry Problem 849: Special Right triangle, Catheti or legs ratio 1:3, 18.5 Degrees, Double angle

Posted by Antonio Gutierrez at 7:21 AM
Labels: , , ,

2 comments:

  1. Michael TsourakakisFebruary 1, 2013 at 6:45 AM

    Is ,AD=DE=EC and EM perpendicular of the AC with EM=AB=c.
    Then ABME,is ,a parallelogram and ADM is, diagonal. So, angle EBM= angle AEB=β
    The triangle DMC is isosceles and rectangular.So,the ABMC , is a cyclic quadrilateral,therefore ,angle AMB=ACB=α.
    Βut ,from the triangle ΒΔΜ we ,angle EBM+ angle AMB=α+β=45.
    Because (problem 848), β= 26,5 degrees ,then α=18,5 degrees
    Image: http://img526.imageshack.us/img526/5597/geogebra3.png

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  2. AnonymousFebruary 20, 2013 at 5:58 PM

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