Wednesday, January 2, 2013

Problem 844: Triangle, Medians, Centroid, Four Circumcenters, Perpendicular, Congruence, Similarity

Geometry Problem
Level: Mathematics Education, High School, Honors Geometry, College.

Click the figure below to see the complete problem 844.

Online Geometry Problem 844: Triangle, Medians, Centroid, Four Circumcenters, Perpendicular, Congruence, Similarity

Posted by Antonio Gutierrez at 6:03 PM
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1 comment:

  1. Jacob HA (EMK2000)January 2, 2013 at 8:12 PM

    In Problem 843, it is easy to show that
    APCG is a parallelogram.
    So CP=AG=2/3×AD, GP=BG=2/3×BE.

    By Problem 843,
    HO3×CP=HO1×GP
    ⇒ HO3×2/3×AD=HO1×2/3×BE
    ⇒ HO3×AD=HO1×BE

    ReplyDelete

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